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RE: MS XML Parser
- From: "Ruane, Conleth" <Conleth dot Ruane at compaq dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 16 Nov 2001 13:07:22 +0100
- Subject: RE: [xsl] MS XML Parser
- Reply-to: xsl-list at lists dot mulberrytech dot com
Thanks Chris, that helped. Now I know where the escaped characters are
getting lost.
What I need now is an appropriate "StringStream" object to pass to
transformNodeToObject instead of a dom.
doc.transformNodeToObject xsl, output
I've tried this:
--------
dim FSO
dim outFile
set FSO = Server.CreateObject("scripting.FileSystemObject")
set outFile =
fso.OpenTextFile(Server.MapPath("ttmp.txt"),2,true)
-------
but I get "Invalid procedure call or argument:
'doc.transformNodeToObject'".
Any suggestions?
Bye
Conleth Ruane
> COMPAQ EMEA HQ IM, Munich
Telephone: +49-89-9392-4393
mailto:Conleth.Ruane@compaq.com
-----Original Message-----
From: Chris Bayes [mailto:chris@bayes.co.uk]
Sent: Friday, November 16, 2001 11:48 AM
To: xsl-list@lists.mulberrytech.com
Subject: RE: [xsl] MS XML Parser
> I'm not looking for a *special* CR I want to output the
> escaped characters that represent the CR. SAXON does it and
> XML-Spy does it (and that actually uses MS XML Parser).
>
Well in fact you are. What you are doing with
<xsl:text
disable-output-escaping="yes">XXXX&#x0D;&#x0A;YYYY</xsl:text>
is generating XXXX
YYYY in the output. When you do this with
saxon or xml-spy you are usually writing out to a file so it stays as
is. With your asp you are transforming it to another dom and I suspect
that it sees the string XXXX
YYYY and converts that to a
single lf.
You can test that by doing a doc.transformNodeToObject xsl, Request
which should stream the XXXX
YYYY directly to the client. If
you really need to go via the third dom then you could try
XXXX&amp;#x0D;&amp;#x0A;YYYY.
Ciao Chris
XML/XSL Portal
http://www.bayes.co.uk/xml
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