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Re: Reformatting character strings

From: Jörg Heinicke <joerg dot heinicke at gmx dot de>
To: xsl-list at lists dot mulberrytech dot com
Date: Fri, 16 Nov 2001 19:23:38 +0100
Subject: Re: [xsl] Reformatting character strings
References: <038329034492D5119B6400D0B7A7C17E425277@tfukmksmsg1.datastream.com>
Reply-to: xsl-list at lists dot mulberrytech dot com

There are much solutions in FAQ and in the list archives. Use substring().

Joerg

Burisch, Curtis wrote:

> Hi,
> 
> As ususal, I'm sorry if this is in the faq but could someone give me a
> pointer on how I can reformat a date (it's in an attribute) from DD/MM/YYYY
> format to MM/DD/YY format?
> 
> Thanks,
> Curtis.


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References:
- Reformatting character strings
  - From: Burisch, Curtis

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