[xsl] Re: Re: Collecting attributes from the ancestor-or-self axis

[Dimitre Novatchev <dnovatchev at yahoo dot com>]

> I believe this works as follows:
> 1. the select in copy-of returns a node-set in document order.  At this
> point the node set has duplicate attribute names.
> 
> I don't think that's right. By definition node-set is "an unordered 
> collection of nodes without duplicates". So all dublicates have to be 
> removed at the time of XPath expresison evaluating and the order may be 
> any one appropriate to XPath processor.
> 

You're mislead of his meaning of "duplicates" here -- by "duplicates" he means
attribute nodes having the same name -- these are not duplicates in XPath, where
node equality is the same as node identity.


> > 2. when copy-of applies these attributes to the output element, the
> > duplication is removed by succeeding attribute nodes overwriting the values
> > of any attributes that are already present.
> 
> <xsl:copy-of> copies nodes in document order, but if you are copying 
> attributes, why do you care about any order?

Order is important here, as from a set of attribute nodes with the same name, only
the last one is output (by the serializer I guess?).


Cheers,
Dimitre Novatchev.




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