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Re: xsl:if @attribute + xsl:variable not working
- From: Alessio Mazzieri <mazzieri at umbrars dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 28 Nov 2001 09:35:01 +0100
- Subject: Re: [xsl] xsl:if @attribute + xsl:variable not working
- References: <001401c177e3$b90cf440$e800005a@Pau>
- Reply-to: xsl-list at lists dot mulberrytech dot com
This is an alternative solution to your problem:
<xsl:for-each select="area">
<td>
<xsl:attribute name="bgcolor">
<xsl:choose>
<xsl:when test="@position=1">
#FF7A0
</xsl:when>
<xsl:otherwise>
#FF980F
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
</td>
</xsl:for-each>
About the message error, I think that the problem is an "out-of-scope"
matter, because both the <xsl:variable> are inside an <xsl:if> element.
Give an eye to Mickeal Kay's XSLT Programmers Reference, page 315: the
same example! :)
Aniceto Lopez wrote:
> Hi all:
> why if
>
> <xsl:for-each select="area">
> <xsl:if test="@position = 1">
> <xsl:variable name="color" select="'#FFF7A0'"/>
> </xsl:if>
> <xsl:if test="@position = 2">
> <xsl:variable name="color" select="'#FF980F"/>
> </xsl:if>
>
> <td bgcolor="{$color}">dadada asda</td>
>
> </xsl:for-each>
>
> I get this?
>
> "A reference to variable or parameter 'colortabla' cannot be resolved.
> The variable or parameter may not be defined, or it may not be in scope."
>
> -> the variable IS in scope (if I define it without xsl:if it works)
> xml -> <area position="1"> or <area position="2">
>
>
> thanks in advance
>
> Aniceto Lopez
>
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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