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Re: for-each order
- From: Trevor Nash <tcn at melvaig dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 14 Dec 2001 17:24:18 +0000
- Subject: Re: [xsl] for-each order
- Organization: Melvaig Software Engineering Limited
- References: <00d201c184d6$78980120$c4c909c0@COHANA>
- Reply-to: xsl-list at lists dot mulberrytech dot com
>Is there a way to do <xsl:for-each ..... and looping backwards.
>
Use xsl:sort, as in:
><xsl:variable name="position">
> <xsl:for-each select="$path">
<xsl:sort select="position()" data-type="number"
order="descending" />
> <xsl:value-of select="@value"/>,
> </xsl:for-each>
></xsl:variable>
(Ref: Mike Kay's XSLT programmers reference, page 297)
Anticipating the obvious question if you want 1,2,3 instead of 1,2,3,
<xsl:if test="position()!=last()">,</xsl:if>
Regards,
Trevor Nash
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voice: +44 (0) 1445 771 271
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