RE: [xsl] De-flattening an XML tree

["Michael Kay" <michael dot h dot kay at ntlworld dot com>]

This is a problem I call "positional grouping". One way to tackle it is to
reduce it to a value-based grouping problem, where the grouping key for a
<record> is it's generate-id(), and for a <data> element is
generate-id(preceding-sibling::record[1]). Then you can use standard
Muenchian grouping as described in
http://www.jenitennison.com/xslt/grouping.

Alternatively, if this is a one-off, why not try the new XSLT 2.0 grouping
facilities available in Saxon 7.0?

<xsl:for-each-group group-starting-at="record">
<record>
  <xsl:for-each select="current-group()[self::data]">
    <xsl:copy-of select="."/>
  </xsl:for-each>
</record>
</xsl:for-each>

Mike Kay



> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Benjamin
> Johnston
> Sent: 09 January 2002 01:25
> To: XSL-List@lists.mulberrytech.com
> Cc: Benjamin Johnston
> Subject: [xsl] De-flattening an XML tree
>
>
>
> Hi,
>
> I'm kind of stuck on ideas for how I might de-flatten a tree. It seems
> that I can't get the position of the next sibling with some
> property and I
> end up going around in circles with checking siblings because filter
> predicates seem to only work with one node at a time.
>
> If I've got something like;
>
> <recordset>
>   <record/>
>   <data/>
>   <data/>
>   <record/>
>   <data/>
>   <record/>
>   <data/>
>   <data/>
>   <data/>
> </recordset>
>
> ie. we've got a record tag, followed by it's "children".
>
> Is there any way of transforming this to:
> <recordset>
>   <record>
>     <data/>
>     <data/>
>   </record>
>   <record>
>     <data/>
>   </record>
>   <record>
>     <data/>
>     <data/>
>     <data/>
>   </record>
> </recordset>
>
>
> Any suggestions, ideas or strategies?
>
> Thanks a lot!
>
> -Benjamin Johnston
> s355171@student.uq.edu.au
>
>
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