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Template match via xsl:param
- From: Mario Lang <mlang at delysid dot org>
- To: XSL-List at lists dot mulberrytech dot com
- Date: 14 Jan 2002 22:03:40 +0100
- Subject: [xsl] Template match via xsl:param
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hello.
I am trying to write some generic stylesheets which I can stack in filterproxy.
>From the archive/FAQ I figure that this isnt as easy as one may think, but
I couldnt find a simple example which illustrates how to do it right.
So, here is what I am trying to do:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="yes"
encoding="iso8859-15"/>
<xsl:param name="path"></xsl:param>
<xsl:include href="identity.xsl"/>
<xsl:template match="$path"/>
</xsl:stylesheet>
Can anyone give me a simple example on how to achieve this without
genereting the xsl file on the fly?
--
CYa,
Mario <mlang@delysid.org>
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