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Re: RE: FW: Path Reversal
- From: Dimitre Novatchev <dnovatchev at yahoo dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 29 Jan 2002 00:44:10 -0800 (PST)
- Subject: [xsl] Re: RE: FW: Path Reversal
- Reply-to: xsl-list at lists dot mulberrytech dot com
For easy extraction of all the "steps" in an XPath expression with
unknown in advance number of "steps" one can re-use an existing
template -- the Functional Tokenizer:
http://aspn.activestate.com/ASPN/Mail/Message/xsl-list/914654
Cheers,
Dimitre Novatchev.
Jarno.Elovirta@nokia.com wrote:
Hip hei,
> Suppose I have the following piece of XML:
>
> <node name="funstuff">
> <node name="jokes">
> <node name="veryfunnyjoke"/>
> </node>
> </node>
>
> I have a path (as a string) which is composed of the @names of the
> nodes. It looks like /funstuff/jokes/veryfunnyjoke. How can I write a
> template (or an EXSLT function) that returns the node the
> path points to
> (e.g. veryfunnyjoke)?
With XSLT 1.0 you can't return the node, but you can write a
named/moded template which is called for the node you want to return.
David McNally already posted a solution, but here's another one with
separate templates to evaluate the step and process the return value -
basically they're the same solution, really.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:text>
/funstuff/jokes2/veryfunnyjoke = </xsl:text>
<xsl:call-template name="parser">
<xsl:with-param name="path"
select="'/funstuff/jokes2/veryfunnyjoke'" />
</xsl:call-template>
<xsl:text>
/funstuff/jokes/veryfunnyjoke2 = </xsl:text>
<xsl:call-template name="parser">
<xsl:with-param name="path"
select="'/funstuff/jokes/veryfunnyjoke2'" />
</xsl:call-template>
</xsl:template>
<xsl:template name="parser">
<xsl:param name="path" />
<xsl:choose>
<xsl:when test="contains($path, '/')">
<xsl:choose>
<xsl:when test="starts-with($path, '/')">
<xsl:for-each select="/">
<xsl:call-template name="step">
<xsl:with-param name="test"
select="substring-before(substring-after($path, '/'), '/')" />
<xsl:with-param name="path"
select="substring-after(substring-after($path, '/'), '/')" />
</xsl:call-template>
</xsl:for-each>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="step">
<xsl:with-param name="test" select="substring-before($path,
'/')" />
<xsl:with-param name="path" select="substring-after($path,
'/')" />
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
</xsl:when>
<xsl:when test="$path != ''">
<xsl:call-template name="step">
<xsl:with-param name="test" select="$path" />
<xsl:with-param name="path" select="''" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="return" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<!-- here always forward $path to parser -->
<xsl:template name="step" >
<xsl:param name="test" />
<xsl:param name="path" />
<xsl:for-each select="node[@name = $test]">
<xsl:call-template name="parser">
<xsl:with-param name="path" select="$path" />
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="return">
<xsl:value-of select="." />
</xsl:template>
</xsl:stylesheet>
Hope this helps in writing the stylesheet you need,
Santtu
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