This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
XPATH for attribute with different namespace from element
- From: Edward dot Middleton at nikonoa dot net
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 4 Feb 2002 12:12:48 +0900
- Subject: [xsl] XPATH for attribute with different namespace from element
- Reply-to: xsl-list at lists dot mulberrytech dot com
I am trying to make a template match for an rss about attribute but I can't seem to get anything to work.
I tried the following, and all other combinations I could think of with no success.
rdf:RDF/channel/@rdf:about
This is my rss file
<?xml version="1.0" encoding="UTF-8"?>
<rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns="http://purl.org/rss/1.0">
<channel rdf:about="newsmlsiteurn">
<title>Various files</title>
<link>http://some.site.com</link>
<description>Various files on some.site</description>
</channel>
<item rdf:about="mayidentifier">
<title>DTD File</title>
<link>dtd\NewsMLv1.0.dtd</link>
</item>
</rdf:RDF>
and my stylesheet is.
<?xml version="1.0"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns="http://purl.org/rss/1.0">
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="rdf:RDF/channel/@rdf:about">
<xsl:value-of select="current()"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:transform>
Thanks in advance
Edward
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list