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xsl:copy

From: "Garrick Besterwitch" <garrickb at infonox dot com>
To: <xsl-list at lists dot mulberrytech dot com>
Date: Tue, 19 Feb 2002 11:39:29 +0530
Subject: [xsl] xsl:copy
References: <E16crud-000ILQ-00@oceanus.uk.clara.net> <3C7146B8.9030707@multiconn.com> <16610638807.20020218185532@jenitennison.com>
Reply-to: xsl-list at lists dot mulberrytech dot com

Hi,
  I need to generate a copy of an xml file using xsl ...I tried using
xsl:copy..but this gives me only the value and not the node names ....Is
there a workaround to accomplish this.

Thanks and cheers
Garry


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Follow-Ups:
- RE: xsl:copy
  - From: Michael Kay

References:
- RE: evaluate() function in XPath 2.0 (Was: Re: Lookup (?))
  - From: Curtis Burisch
- Re: evaluate() function in XPath 2.0 (Was: Re: Lookup (?))
  - From: Oleg Tkachenko
- Re: evaluate() function in XPath 2.0 (Was: Re: Lookup (?))
  - From: Jeni Tennison

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