Re: [xsl] position of non actual element

["Rudolf Pischek" <rudolf dot pischek at asei dot cz>]

Hi oliviere,
>position() returns always the position of the current node within the
>context node list. There's nothing like a "global position".
I know :-))

>So, what do you mean by "position"?
ok, my original data are:

<table>
  <cols>
    <col name="persno" width="..." align=".." grid="..." .....>
    <col name="name" width="..." align=".." grid="..." .....>
    <col name="address" width="..." align=".." grid="..." .....>
  </cols>
  <rows>
    <row memo="..">
      <cell>123</cell>
      <cell>John Smith</cell>
      <cell>1st avenue, 1040 Boston</cell>
    </row>
    ...
  </rows>
</table>

When I format this xml I want:
<xsl:for-each select="table/rows/row">
  <TR><TD><xsl:value-of select="give me the cell which position is the same
as the position of element col which attribute is name"/>
      </TD>
  </TR>
</xsl:for-each>

Thats all what I want. I think if you write select="element[position() = 5]"
that means that parser must find position of "element", why I cannot know
the number of this position(), why only in test?

Rudolf Pischek



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