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Counting proceding elements with the attribute value
- From: "Niklas Gustavsson" <niklas at protocol7 dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Sun, 7 Apr 2002 23:02:47 +0200
- Subject: [xsl] Counting proceding elements with the attribute value
- References: <BBEJKGIELKMFIMGJKDMNKEOJDMAA.woloski@sion.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi
I'm sure this question have a very simple answer that I have overlooked :-)
I have a XML document with the following structure:
<nodes>
<node name="a">
<!-- some XML -->
</node>
<node name="b">
<!-- some XML -->
</node>
<node name="b">
<!-- some XML -->
</node>
<node name="b">
<!-- some XML -->
</node>
<node name="c">
<!-- some XML -->
</node>
</nodes>
Then I have this XSLT fragment:
<xsl:template match="node">
<xsl:value-of select="@name" />
<xsl:if test="following-sibling::attr/@name = @name or
preceding-sibling::attr/@name = @name">
<!-- here I want to output the number of proceding elements with the same
value in the name attribute -->
</xsl:if>
</xsl:template>
But, I can not think of any way of getting the number of proceding elements
with the same value in the name attribute. Or rather, how to select the node
set with that condition.
The final result I want is:
a
b 1 (3)
b 2 (3)
b 3 (3)
c
Any help? :-)
Thanks!
/niklas
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