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RE: last(): selecting the last one?
- From: Jarkko dot Moilanen at uta dot fi
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 23 Apr 2002 11:18:08 +0300 (EEST)
- Subject: RE: [xsl] last(): selecting the last one?
- References: <E392EEA75EC5F54AB75229B693B1B6A70E25F6@esebe018.NOE.Nokia.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
> Heppa,
>
> > Hmmm.... No. Since the order of the result should be like
> > above and then
> > find the latest concerning both date and time+ select it's
> > topic element
> > value.
>
> Yes, but *where* do you want to do that? Inside the template selection
> that generates that list, or outside? If it's the latter, then
Yes the latter one in this case. And thanks, it works now =)
>
> variable name="latest"
> for-each select="message"
> sort select="the xpath to sort the data"
> sort select="the xpath to sort the time"
> if test="position() = last()"
> value-of select="topic"
>
> will set the $latest variable to the value of the topic element of the
> latest message.
>
> Cheers,
>
> Santtu
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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Jarkko Moilanen *You are wise, witty, and wonderful, *
Researcher/ ITCM *but you spend too much time *
jarkko.moilanen@uta.fi *reading this sort of trash. *
www.uta.fi/~jm60697 * *
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