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RE: replace xml element
- From: "Michael Kay" <michael dot h dot kay at ntlworld dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Wed, 1 May 2002 10:29:59 +0100
- Subject: RE: [xsl] replace xml element
- Reply-to: xsl-list at lists dot mulberrytech dot com
Write a template rule for each element saying how you want that element to
be processed:
<xsl:template match="content">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="break>
<br/>
</xsl:template>
You might want to add a default rule that copies elements unchanged:
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
or that deletes elements together with their content:
<xsl:template match="*"/>
or that processes the contents of the element but drops the start and end
tag:
<xsl:template match="*">
<xsl:apply-templates/>
</xsl:template>
Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of valerie
> liston
> Sent: 01 May 2002 09:27
> To: XSL-List@lists.mulberrytech.com
> Subject: [xsl] replace xml element
>
>
> I have a question about replacing xml elements. Here is the problem;
> I want to output the content of the element <content> and replace the
> element <break/> with the html tag <br/>. I know this is
> probably a very
> basic question but I appreciate your help.
> <item name="netinterfacedes" translation="Network Interface
> Description">
>
> <par type="text">
>
> <content>Intel Pro/100 VE Network connection<break/>10 Base-T and 100
> Base-TX physical layer capabilities<break/>Remote wake on LAN
> supported</content>
>
> </par>
>
> </item>
>
> <xsl:value-of select="item/par/content"/>
>
> Thanks
>
>
>
>
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