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Re: <xsl:for-each> help
- From: "Zoe Peng" <zoe at allfools dot net>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 1 May 2002 18:49:39 -0400
- Subject: Re: [xsl] <xsl:for-each> help
- Reply-to: xsl-list at lists dot mulberrytech dot com
c..
thanks.
--Zoe
> [Zoe Peng]
>
> > many thanks.
> > I won't be able to use <xsl:if test...> cuz the xml document is
> > generate on the fly and the key is coming from parameter. But, I got
> > what I need. It outputs "My News".
> >
> > This is what I want:
> > <xsl:for-each select='dynamictree/category[@id="1"]'>
> > <xsl:for-each select='service[@id="01"]'>
> > servicename: <xsl:value-of select="@name" />
> > </xsl:for-each>
> > </xsl:for-each>
>
> Glad I could help. I don't think you need the double for-each,
though,
> depending on what else you do in them that you haven't explained.
Just by
> what you have shown, a single for-each would do what you need. You
could use
>
> <xsl:for-each
> select='dynamictree/category[@id="1"]/service[@id="01"]'>
>
> Depending on whether there would be more than one of them, you might
not
> even need to use any for-each at all, just the value-of.
>
> Cheers,
>
> Tom P
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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