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Re: xpath - how to return all nodes but the node matching avalue in an arbitrary tree?
> <xsl:param name="delete_id"/>
> <xsl:template match="/">
> <xsl:copy-of select="//category//artist[@id!=$delete_id]"/>
> </xsl:template>
You select all artist-elements, which don't have the $delete_id. This
works for me.
But I think you want something different. Try a copy whith each node
separately:
<xsl:param name="delete_id"/>
<xsl:template match="*|text()|@*">
<xsl:copy>
<xsl:apply-templates select="*[@id != $delete_id]|text()|@*"/>
</xsl:copy>
</xsl:template>
This stylesheet would copy the complete input to the output.
A little change at the apply-templates removes the elements which should
be deleted:
<xsl:apply-templates select="*[@id != $delete_id]|text()|@*"/>
Regards,
Joerg
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