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RE: Carlos Problem (II) how to show some results y some places:
- From: TSchutzerWeissmann at uk dot imshealth dot com
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 10 May 2002 10:43:48 +0100
- Subject: RE: [xsl] Carlos Problem (II) how to show some results y some places:
- Reply-to: xsl-list at lists dot mulberrytech dot com
Carlos wrote:
>is a very good method but i need other thing; in the fist td 1 4 7
elements,
>in the second 2 5 8 in the tree elemnt 3 6 9
>can anybody help me please, i must to solve this problem in my hob, i am
>exasperated, i am working in this problem one week and i cannot solve.
>please help me
>
>
>i want to present in this form:
><table>
><tr>
><td>1 4 7....</td><td>2 5 8....</td><td>3 6 9....</td>
></tr>
></table>
>and i dont want:
><table>
><tr>
><td>1</td><td>2</td><td>3</td>
></tr>
><tr>
><td>4</td><td>5</td><td>6</td>
></tr>
><tr>
><td>7</td><td>8</td><td>9</td>
></tr>
></table>
Hello Carlos,
Let say you want 3 columns. That means:
in column 1 you want element 1 (1 mod 3 = 1) , 4 (4 mod 3 = 1), 7 (7 mod 3 =
1)
In column 2: 2, 5, 8 (5 mod 3 = 2) etc.
In fact, it looks as if with x columns, for column c you want elements where
position() mod x = c.
BUT
in column 3: 3 mod 3 = 0: this is the exception.
The stylesheet below uses a for-each to get the first 3 elements and uses
them to generate a variable called $mod, which counts from 1 to the number
of columns desired (in this case, 3), but ensures that the last value is a
0. So it counts 1 to 3 like this: 1, 2, 0.
The second for-each goes through all the REGISTRO elements, and groups them
according to the scheme explained above.
It should be fairly easy to adapt this method as a mode in your existing
stylesheet. Good luck,
Tom Weissmann
<?xml version='1.0' encoding='UTF-8' standalone='yes'?>
<xsl:stylesheet version='1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
<xsl:template match='/'>
<html>
<body>
<xsl:apply-templates select='/INMOBILIARIAS'>
<xsl:with-param name ="colCount" select
="3"/>
</xsl:apply-templates>
</body>
</html>
</xsl:template>
<xsl:template match="INMOBILIARIAS">
<xsl:param name="colCount" select="/.."/> <!-- the number of
columns to span -->
<table>
<tr> <!-- it looks like you only want just one row -
maybe -->
<xsl:for-each select="REGISTRO[position() <=
$colCount]">
<!-- the first for-each - count 1 to $colCount -->
<xsl:variable name='mod'>
<xsl:choose>
<!-- for the $colCount-th set, $mod
needs to be 0, not $colCount -->
<xsl:when test='position() mod
$colCount = 0'>
0
</xsl:when>
<xsl:otherwise>
<xsl:value-of
select='position()'/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<td>
<xsl:for-each
select="../REGISTRO[position() mod $colCount = $mod]">
<xsl:sort
select='position()'/>
<xsl:value-of
select="./REFERENCIA"/>
</xsl:for-each>
</td>
</xsl:for-each>
</tr>
</table>
</xsl:template>
</xsl:stylesheet>
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