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Re: Generating a list of items NOT present in source XML
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 17 May 2002 18:17:28 +0100
- Subject: Re: [xsl] Generating a list of items NOT present in source XML
- References: <5.1.0.14.0.20020517105440.00a952a8@parzival.integretechpub.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
It depends a bit what your missing nodes are, if it's numbers then the
stylesheet has a chance, if the thing is a list of family birthdays and
I've forgotten one (not uncommon:-) then the stylesheet probably won't
have much of a chance of filling in the gaps. (Hmm now there's a
challenge for Jeni, can she provide a stylesheet that will fill in my
Mum's birthday...)
Anyway for your example,
<xsl:for-each select="//*[position()</root/obj]">
<xsl:if test="not(position() = /root/obj)">
<obj><childnode><xsl:value-of select="position()"/></childnode></obj>
</xsl:for-each>
probably works, but not if node 10 was missing.
David
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