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RE: Grouping question
- From: bryan dot s dot schnabel at exgate dot tek dot com
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 21 May 2002 10:31:41 -0700
- Subject: RE: [xsl] Grouping question
- Reply-to: xsl-list at lists dot mulberrytech dot com
While we wait for Jeni to give us the well-thought-out XSLT 1.0 Meunchian
method, here's some fun to consider with XSLT 2.0.
Assuming your input is well formed (not </color>):
<data>
<n color="R">1</n>
<n color="R">2</n>
<n color="R">3</n>
<n color="Y">4</n>
<n color="Y">5</n>
<n color="Y">6</n>
<n color="W">7</n>
<n color="W">8</n>
<n color="W">9</n>
</data>
Something like this would work:
<xsl:template match="data">
<tables>
<xsl:for-each-group select="n" group-by="@color">
<xsl:sort select="." />
<table>
<xsl:for-each select="current-group()">
<xsl:if test="position() mod 2">
<xsl:variable name="color" select="@color" />
<tr>
<td>
<xsl:value-of select="." />
</td>
<xsl:if test="following-sibling::n[@color=$color]">
<td>
<xsl:value-of select="following-sibling::n[@color=$color]" />
</td>
</xsl:if>
</tr>
</xsl:if>
</xsl:for-each>
</table>
</xsl:for-each-group>
</tables>
</xsl:template>
Bryan
-----Original Message-----
From: Spectron International, Inc. [mailto:spectron@coqui.net]
Sent: Tuesday, May 21, 2002 7:05 AM
To: XSL-List@lists.mulberrytech.com
Subject: [xsl] Grouping question
I have the following XML:
<data>
<n color="R">1</color>
<n color="R">2</color>
<n color="R">3</color>
<n color="Y">4</color>
<n color="Y">5</color>
<n color="Y">6</color>
<n color="W">7</color>
<n color="W">8</color>
<n color="W">9</color>
</data>
and I want to create 3 tables (one for each color) with 2 columns each:
<table>
<tr><td>1</td><td>2</td></tr>
<tr><td>3</td></tr>
</table>
<table>
<tr><td>4</td><td>5</td></tr>
<tr><td>6</td></tr>
</table>
<table>
<tr><td>7</td><td>8</td></tr>
<tr><td>9</td></tr>
</table>
I have checked the grouping section in http://www.dpawson.co.uk/xsl/ but
none of the samples do what I need. How can I do that?
Faw
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