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passing parameter to template
- From: ChivaBaba at aol dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Wed, 29 May 2002 10:03:18 EDT
- Subject: [xsl] passing parameter to template
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi folks,
I'm facing a problem while trying to pass a parameter to a template. The corresponding xsl-code is the following:
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
<xsl:apply-templates select="exsl:node-set($tools)">
<xsl:with-param name="sort">
<xsl:value-of select="$sort_dir"/>
</xsl:with-param>
</xsl:apply-templates>
..
..
<xsl:template match="tool">
<xsl:param name="sort"/>
...
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
My param "sort" is empty!! How can I pass the value to my template?????
(when I use <xsl:apply-templates select="tool"> then it works but I have to use the variable "tools"!!)
Many thanks for any help,
Stefan
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