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Re: passing parameter to template
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 29 May 2002 15:51:34 +0100
- Subject: Re: [xsl] passing parameter to template
- References: <138.efd5687.2a2639a7@aol.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
> <xsl:apply-templates select="exsl:node-set($tools)">
that applies templates to the root node, so you either need to have
a template for / that handles the parameter or you need to do
<xsl:apply-templates select="exsl:node-set($tools)/*">
^^
so you pass apply templates to the first element, so if that is
<tool> the template you showed would have the param.
> <xsl:with-param name="sort">
> <xsl:value-of select="$sort_dir"/>
> </xsl:with-param>
Unless you particularly want to create a result tree fragment here
(which is unlikely) you would be much better off doing
<xsl:with-param name="sort" select="$sort_dir"/>
David
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