[xsl] RE: how I can select the largest attribute value

[Henk Meulekamp <henkm at ccni dot nl>]

Maybe you can do something like this?

<xsl:for-each select="Root/element[1]">
	<xsl:sort select="@length" data-type="number" order="descending"/>
		<xsl:value-of select="@length"/>
</xsl:for-each>

| -----Original Message-----
| From: Bodrul Haque [mailto:Bodrul.Haque@synergy-logistics.co.uk] 
| Sent: dinsdag 18 juni 2002 16:23
| To: 'xsl-list@lists.mulberrytech.com'
| Subject: 
| 
| 
| Hi List,
| 
| Can someone please tell me how I can select the largest 
| attribute value from the following xml file, without doing 
| 
| <xsl:value-of select="Root/element[@length="14"]/@length" />. 
| 
| (I don't want to use a hard coded value in the predicate). Is 
| there an Xpath that i can use. Xml file: <Root>
|      <element  length="3" />
|      <element  length="14" />
|      <element  length="1" />
|      <element  length="6" />
|      .....
| </Root>
| 
| I'm using MSXML3.
| 
| Thanks in Advance
| 
| Bodrul
| 
| 
|  
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