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Re: Finding out the existence of a node
- From: Oleg Tkachenko <olegt at multiconn dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Mon, 01 Jul 2002 14:10:44 +0200
- Subject: Re: [xsl] Finding out the existence of a node
- Organization: Multiconn International Ltd
- References: <20020701104948.22197.qmail@webmail18.rediffmail.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
What about
<xsl:if test="document($source)/descendant::*[local-name()=$node_name]">
Kalyan Kumar Mudumbai wrote:
Hi,
is there a way to find out if a particular node exists in an xml
file or not?
For example, I have an xml file which has a node <MyName>, how can I
know if the same node is also present in another xml file which the
stylesheet is processing?
<xsl:variable name="node_name" select="local-name()"/>
gives me the name of the node into the variable node_name.
<xsl:param name="source" select="./Doc.xml"/>
gives selects the path of Doc.xml into $source
Now how do I know whether $node_name is present in Doc.xml or not?
Please help me out.
Thanks,
Kalyan
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Oleg Tkachenko
Multiconn International Ltd, Israel
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list