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RE: Finding out the existence of a node
- From: "Michael Kay" <michael dot h dot kay at ntlworld dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 1 Jul 2002 15:27:47 +0100
- Subject: RE: [xsl] Finding out the existence of a node
- Reply-to: xsl-list at lists dot mulberrytech dot com
> Hi,
> is there a way to find out if a particular node exists in an
> xml file or not?
> For example, I have an xml file which has a node <MyName>, how can
> I know if the same node is also present in another xml file which
> the stylesheet is processing?
A node can only be present in one document. I guess you mean you want to
test if the other document has at least one node with the same name.
<xsl:if test="document('other.xml')//*[name()=name(current())]">
Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com
>
> <xsl:variable name="node_name" select="local-name()"/>
> gives me the name of the node into the variable node_name.
>
> <xsl:param name="source" select="./Doc.xml"/>
> gives selects the path of Doc.xml into $source
>
> Now how do I know whether $node_name is present in Doc.xml or not?
> Please help me out.
>
> Thanks,
>
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>
>
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