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XPath iteration?
- From: Derek Davies <ddavies at itasoftware dot com>
- To: XSL-List at lists dot mulberrytech dot com
- Date: Thu, 11 Jul 2002 18:12:45 -0400
- Subject: [xsl] XPath iteration?
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
I'm sorry if this question is inappropriate here, but I haven't found
a more appropriate place to ask, nor have I found a FAQ that addresses
my question.
I'm trying to come up with an XPath expression that will "iterate".
What I have in mind is something to the effect of:
/Root/SomeNode[position()!=position(/Root/SomeNode)]
which would compare each SomeNode against all other SomeNode's except
itself (there are multiple SomeNode children of /Root).
I don't want to explicitly enumerate the SomeNode's. I have a feeling
this isn't possible in XPath (I know it's trivial with XSL).
Would someone care to shed some light on this for me?
Thanks,
Derek
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