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Re: XSLTC key() with for-each Problem
- From: Troy Thibodeaux <troythibodeaux at cox dot net>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 12 Jul 2002 17:13:21 -0500
- Subject: Re: [xsl] XSLTC key() with for-each Problem
- References: <4.2.2.20020712142251.00b4f530@mail.advance.net>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Joerg,
I was afraid that might be the answer.
Thanks for taking the time to consider my problem.
Troy
At 11:16 PM 7/12/2002 +0200, you wrote:
Is there any other way to force the key() function to refer to the nodes
in $old_file? The name of the old file is being passed into the
stylesheet as a parameter, so I don't believe it can be directly
referenced in <xsl:key>.
<xsl:key> works per XML tree, you don't specify a special one (or a
document) in the key-declaration. With your <xsl:for-each
select="$oldfile"> you only change the context document for the key to work on.
So there is no work around if there is really a bug in XSLTC. Either you
use the inefficient method or must wait until the bug is fixed.
Joerg
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