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RE: The longest node in a node set
- From: "Michael Kay" <michael dot h dot kay at ntlworld dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 19 Jul 2002 10:48:46 +0100
- Subject: RE: [xsl] The longest node in a node set
- Reply-to: xsl-list at lists dot mulberrytech dot com
To add to Jeni's reply:
In XPath 2.0, the way you do this is:
max(for $n in $nodeset return string-length($n))
In Saxon 6.5.x, you can do it with an extension function:
saxon:max($nodeset, saxon:expr('string-length(.)'))
(Both of these give you the length of the longest node, not the node
itself)
But for pure XSLT 1.0/XPath 1.0, Jeni has given you the answer.
Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of
> Antonio Fiol Bonnin
> Sent: 18 July 2002 19:05
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] The longest node in a node set
>
>
> Hello,
>
> I am trying to find an XPath expression that gives me the longest
> element in a node set.
>
> I know how to do that for an attribute. e.g //element[not(@attr <
> following-sibling::element/@attr)]
>
> But how can I do that for the string-length(element).
>
> I tried //element[not(string-length(.) <
> string-length(following-sibling::element))]
>
> But this obviously does not work, because
> following-sibling::element is
> not an element or string, but a node-set.
>
> Any ideas?
>
> (I think this one is for Michael Kay... Am I wrong?)
>
> Thank you very much.
>
>
> Antonio Fiol
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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