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RE: Hierarchy problem
- From: DPawson at rnib dot org dot uk
- To: xsl-list at lists dot mulberrytech dot com
- Date: Mon, 22 Jul 2002 12:20:14 +0100
- Subject: RE: [xsl] Hierarchy problem
- Reply-to: xsl-list at lists dot mulberrytech dot com
> -----Original Message-----
> From: Jeni Tennison [mailto:jeni@jenitennison.com]
> Sent: 22 July 2002 10:54
> To: xsl-list@lists.mulberrytech.com
> Subject: Re: [xsl] Hierarchy problem
>
>
> Dave,
>
> David C made a typo when he wrote:
> >> just if $y is a child of $x which is what I think you mean
> by direct
> >> descendant.
> >>
> >> count($x//*|$y) = count($x/*)
> >>
> >> if $y is a descendent of $x
>
> He meant:
>
> count($x//*|$y) = count($x//*)
> ^ additional /
That's it.
<level1 id='l1'>
<h1>Level1</h1>
<level2 id='l2'>
<h2>Level2</h2> <!-- bad navPoint 1 -->
<level3 id='l3'> <!-- good navPoint 2 -->
<h3>level3</h3>
<note id="noteId"> <!-- navLabel target -->
<p>Note content</p>
</note>
</level3>
</level2>
</level1>
<xsl:variable name='x' select='/level1/level2/level3/note'/>
<xsl:variable name='y' select='/level1'/>
<xsl:template match="/">
<xsl:message>Y is a desc of X:<xsl:value-of
select="count($x//*|$y) = count($x/*)"/></xsl:message>
<xsl:message>X is a desc of Y:<xsl:value-of
select="count($y//*|$x) = count($y//*)"/></xsl:message>
</xsl:template>
Gives:
Y is a desc of X:false
X is a desc of Y:true
In this case note is a descendent of level1, so $x should be a descendent of
$Y.
This goes back to the idea of the union ignoring duplicates (count only
once)?
hence
count($x//*|$y) = count($x//*)
implies that node $y is a member of the set which is all the children of $x?
Is that right?
Still doesn't resolve my original problem though.
the hierarchy above is
level1
level2
level3
I'm looking for *immediate* descendent, i.e. level3 (and hence note)
are not *immediate* descendents of level1, level2 intervenes.
I'm playing with Dimitres suggestion, along the lines of
var myNearestParentLevel = substring-after(ancestor-or-self(contains
(name('level')) ...
i.e. get '3' for note as being the nearest wrapper.
then use Dimitres ideas to check if (for level1) l+1 = $myNearestParentLevel
which is false.
Regards DaveP
regards DaveP
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