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Re: Acheiving ..2nd level grouping but with different node structure ..
- From: Jeni Tennison <jeni at jenitennison dot com>
- To: "KUMAR NINGASHETTY" <kningashetty at deltafunding dot com>
- Cc: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 24 Jul 2002 18:56:33 +0100
- Subject: Re: [xsl] Acheiving ..2nd level grouping but with different node structure ..
- Organization: Jeni Tennison Consulting Ltd
- References: <sd3eae36.020@deltafunding.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Kumar,
> Thank you so much for the solution while i was away.... I think
> there is one more problem in this ..correct me if i am wrong .. It
> can only pull data from a <uwr> nodeset only and not from <arr> .
At the point where you're having problems:
<xsl:for-each
select="key('distinct-region', @reg)
[generate-id() =
generate-id(key('distinct-reg-user',
concat(@userid, '+', @reg)))]">
<tr>
<!-- So From here how do i get same 'users' from <ARR> which
is a sibling of this -->
</tr>
</xsl:for-each>
the current node is a los element within the <uwr> element. Presumably
you want to get hold of the los element within <arr> element that has
the same userid and reg as the los element that you're currently on.
To do that, use the 'distinct-reg-user' key -- it will return both the
los elements with the same userid and reg, the first from <uwr> and
the second from <arr>, and you can create the pair of cells for each
of them:
<xsl:for-each select="key('distinct-reg-user',
concat(@userid, '+', @reg))">
<td> <xsl:value-of select="review[@type='N']"/></td>
<td> <xsl:value-of select="review[@type='Y']"/></td>
</xsl:for-each>
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
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