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Re: How do I do this?
- From: Mike Brown <mike at skew dot org>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Wed, 21 Aug 2002 13:59:30 -0600 (MDT)
- Subject: Re: [xsl] How do I do this?
- Reply-to: xsl-list at lists dot mulberrytech dot com
SoumenS@Atoga.com wrote:
> I have a XML based message specification as follows
>
> <message-text><param/> xxxxx yyyy <param/> zzzz bbbb <param/>
> hhhh<param/></message-text>
>
> I would like to convert it to
>
> <file-text>{0} xxxxx yyyy {1} zzzz bbbb {2} hhhh{3}<file-text>
>
> I need to be within the for loop of param and text(), i.e.,
>
> <xsl:for-each select='param | text()'>
>
> Within this for loop how do I get the param number -- position() would not
> work.
Like this: count(preceding-sibling::param)
If I were you, I would not use a for-each, because it results in the same
template (the content of the for-each) being applied to both text nodes and
param elements. I would do this instead:
<xsl:template match="message-text">
<file-text>
<xsl:apply-templates/>
</file-text>
</xsl:template>
<xsl:template match="param">
<xsl:value-of select="concat('{',count(preceding-sibling::param),'}')"/>
</xsl:template>
letting the built-in template for text nodes take care of the character data.
- Mike
____________________________________________________________________________
mike j. brown | xml/xslt: http://skew.org/xml/
denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/
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