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Re: Creating intermediate XML fragment


Of course
i'm sorry not to have explained it .
The rules are
(0) @name = name1 = @ name2
(1) print foobar/@name if it is not ( in bar/@name1 or in bar/@name2 or in foo/@name)
(2) print bar/@name1 if it is not in foo/@name
(2') print bar/@name2 if it is not in foo/@name
(3) Don't print foo/@name

It's your second guess (i think)
Thanks once more for your help

alex

Peter Davis wrote:

On Wednesday 18 September 2002 02:05, alexandre bord wrote:

Hello !
Suppose my (piece of) xml looks like this :
<foobar name="fff" />
<foobar name="dddd" />
<bar name1="dddd" name2="xxx"/>
<bar name1="xxx" name2="yyy"
<foo name="yyy" />
<foo name="zzz" />

No need for an intermediate fragment. This is a simple grouping problem, just with the additional complexity of the different meanings of the different elements.

I'm a little confused on your logic though.


I'd like to output :
fff
dddd (once)
xxx (once)
(not 'yyy' nor 'zzz')

Let me try and guess the rules:

* For <foobar> elements, output @name if it is the first of (foobar/@name|bar/@name1|bar/@name2) with the given value.

* For <bar> elements, output @name1 and @name2 if they are the first of (foobar/@name|bar/@name1|bar/@name2) with the given value and if the value is not a value of a foo/@name.

Or, another guess:

* You want to treat foobar/@name, bar/@name1, and bar/@name2 as all the same, and foo/@name is always not output?

I'd be happy to help suggest a solution, but I don't want to waste my time if my guesses are not correct. Can you clarify a little bit?




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