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Re: Selecting a random node from source-tree
- From: Dimitre Novatchev <dnovatchev at yahoo dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Thu, 26 Sep 2002 08:11:43 -0700 (PDT)
- Subject: [xsl] Re: Selecting a random node from source-tree
- Reply-to: xsl-list at lists dot mulberrytech dot com
"Martin Lormes" <martin dot lormes at gmx dot net> wrote:
> In XSLT 1.0
> How do I select a random node from the source-tree or from an
external
> document?
> I was thinking of an XPath expression like this:
>
> document('funnies.xml')/funnies/quote[random()]
>
> Can I avoid using extension elements?
Yes, use the "randNext" template from FXSL.
More information is contained in the article:
"Casting the Dice with FXSL: Random Number Generation Functions in
XSLT"
http://fxsl.sourceforge.net/articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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