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RE: Re[2]: how calculate sum(x*y)
- From: Jarno dot Elovirta at nokia dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Mon, 7 Oct 2002 12:42:05 +0300
- Subject: RE: Re[2]: [xsl] how calculate sum(x*y)
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
> >> how calculate sum(x*y) ??
> >>
> >> IF i try use sum() it say that need only node-list as argument....
> >>
> >> I have xml
> >> <root>
> >> <data>
> >> <x>2</x>
> >> <y>3</y>
> >> </data>
> >> <data>
> >> <x>5</x>
> >> <y>6</y>
> >> </data>
> >> .....
> >> <root>
>
> JEnc> Write a recursive template, that goes through all the
> data elements, summing the multiplication result to previous
> result sum, i.e.
>
> JEnc> template name=sum
> JEnc> param name=node-set
> JEnc> param name=sum
>
> JEnc> if count($node-set') = 0
> JEnc> then
> JEnc> value-of select=$sum
> JEnc> else
> JEnc> call-template name=sum
> JEnc> with-param name=node-set
> select=$node-set[not(position() = 1)]
> JEnc> with-param name=sum select=$sum + $node-set[1]/x
> * $node-set[1]/y
>
> JEnc> Dimitri probably has some suitable function for the
> job, see [http://fxsl.sourceforge.net/].
>
>
> I try now use function "nodeset" from xalan namespace to
> build new nodeset
> with result of calculation x*y and then apply function sum for this
> tree.
> can you compare this two variants, what variant more likely to use ?
Well, exslt:node-set is pretty portable these days (latest Xalan implements it), but I don't see any particular reason why you couldn't just use the XSLT 1.0 way of doing it. If you need the intermediate multiplication result set somewhere else, then the RTF->node-set solution will probably be better, but if you just need the multiplication sum, go with the recursive template.
Cheers,
Jarno - Cenobita: Destino Final (Global mix)
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