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Re: make 3.80 and VPATH
On Fri, Jul 11, 2003 at 07:55:38PM -0700, Christopher Seawood wrote:
>Christopher Faylor wrote:
>
>> Then, we need to know *how*you*are*running*make*.
>
>We're just typing 'make', which unless something changed, should be the
>same as 'make --unix'. 'make -p | grep MAKE_MODE' returns 'MAKE_MODE =
>unix'. Hmm. I do see that /etc/profile is setting MAKE_MODE=unix so
>that may not be make's default.
If you are just running make, then how could VPATH be expected to translate
MS-DOS paths into UNIX paths?
>> You don't have to go into exhaustive detail about how mozilla works.
>> You just need a (probably) three line makefile and a copy of the make
>> command line and, if you are using it, description of the MAKE_MODE
>> environment variable setting.
>>
>> I am not trying to be difficult. I have tried to construct my own test
>> case and, AFAICT, it works fine.
>>
>> I run it like thist:
>>
>> make --win32 -f mkfile
>>
>> mkfile contains:
>>
>> VPATH=c:/tmp
>> all: remount.bat
>> echo $?
>>
>> remount.bat exists in c:/tmp.
>
>That example works fine if I do 'make --win32' but fails when just using
>'make'. That is a change in behavior from the previous version of make.
> The testcase works with either of --unix & --win32 when using make
>3.79.1-7 .
As it should. Colon is a path separator. So, to answer your question, yes
it is by design that VPATH is not translating MS-DOS paths. If it was doing
so before, it was clearly a bug.
cgf
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