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Re: Bug in POSIX.2 regex word boundary matching


Bleah. #include statements were missing in my
previously posted sample test case.  Here
is the test case again with #include statements
this time:

$ cat regex-bug.c

#include <stdio.h>
#include <regex.h>
#include <stdlib.h>

int main()
{
  regex_t    r;
  regmatch_t pmatch[2];

  if (regcomp(&r, "\\bfoobar\\b", REG_EXTENDED) != 0) {
    fprintf(stderr, "regcomp failed\n");
    exit(-1);
  }

  /* I'd expect above regex to match following string */
  if (regexec(&r, "test foobar test", 2, pmatch, 0) == 0) {
    fprintf(stderr, "OK (match)\n");  /* expected behavior */
  } else {
    fprintf(stderr, "FAIL (mismatch)\n"); /* unexpected!? */
  }
  return 0;
}

$ gcc regex-bug.c
$ ./a.out

Outcome on Cywgin ................ FAIL (mismatch)

Outcome on Linux (Ubuntu-5.10) ... OK (match)

Cheers
-- Dominique

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